显示日期和月份，根据区域设置不显示年份-尊龙凯时

问题描述

有没有更好的方法从包含位置适当分隔符的日期中仅获取日和月?

is there any better way for getting only day and month from a date including location appropriate separator?

我有一个先获取分隔符的尊龙凯时的解决方案:

i have a solution that gets separator first:

 function getdatesep() {
   var temp = moment().format('l');
   var locale = moment().locale;
   var datesep = temp.substring(5, 6);
   return datesep;
}

然后像这样构建日期:

var sep = function getdatesep()
var date = date.format('d'   sep   'm'  sep)

是否有动态构建整个日期的尊龙凯时的解决方案?

is there a solution that builds the whole date dynamically?

我想要达到的结果是:31.01 (dd.mm)31/01 (日/毫米)01.31 (mm.dd)01/31 (mm/dd) 等

the result i want to achieve would be like: 31.01 (dd.mm) 31/01 (dd/mm) 01.31 (mm.dd) 01/31 (mm/dd) etc

推荐答案

如链接问题中所述:实现所需的一种方法是获取本地化 longdateformat，然后使用正则表达式删除年份部分.

daniel t. 在评论中强调该尊龙凯时的解决方案不适用于 en-ca 等语言环境，因此我将提供考虑到 一些 的更新尊龙凯时的解决方案> 以年份部分开头的其他语言环境.

daniel t. highlighted in comments that the solution will not work in locales like en-ca, so i'm going to provide an updated solution that takes in account some other locales that starts with year part.

如果您需要支持 every 语言环境，您可以使用 ad hoc 条件来定位它们，就像我在以下代码段中为 ar-ly 所做的那样.

probably there are some other locales the are not convered with /.yyyy/ and /yyyy./ regexp, if you need to support every locale you can target them with ad hoc condition, as i made for ar-ly in the following snippet.

这里的代码示例显示了不同语言环境中可能的输出:

here a code sample the shows possible output in various locales:

function changelang(value){
  moment.locale(value);
  
  // get locale data
  var localedata = moment.localedata();
  var format = localedata.longdateformat('l');
  
  // manage custom cases
  if( value === "ar-ly"){
    format = 'd/u200fm';
  }
  // if( value === ...) possible othter cases
  
  // check locale format and strip year
  if( format.match(/.yyyy/g) ){
    format = format.replace(/.yyyy/, '');
  }
  if( format.match(/yyyy./g) ){
    format = format.replace(/yyyy./, '');
  }
  var res = moment().format(format);
  
  $("#result").html(res);
}