亖呉?盀
问题描述
我有这样的代码:
a = "u0432"
b = u"u0432"
c = b"u0432"
d = c.decode('utf8')
print(type(a), a)
print(type(b), b)
print(type(c), c)
print(type(d), d)
然后输出:
в в b'\u0432' u0432
为什么在后一种情况下我看到的是字符代码，而不是字符?如何将 byte 字符串转换为 unicode 字符串，以便在输出时我看到的是字符而不是其代码?
why in the latter case i see a character code, instead of the character? how i can transform byte string to unicode string that in case of an output i saw the character, instead of its code?
推荐答案
在字符串(或 python 2 中的 unicode 对象)中，u 有一个特殊的含义，即这里来了一个 unicode由它的 unicode id 指定的字符".因此 u"u0432" 将产生字符 в.
in strings (or unicode objects in python 2), u has a special meaning, namely saying, "here comes a unicode character specified by it's unicode id". hence u"u0432" will result in the character в.
b'' 前缀告诉你这是一个 8 位字节序列，并且 bytes 对象没有 unicode 字符，所以 u 代码没有特殊意义.因此，b"u0432" 只是字节的序列 ,u,0,4、3 和 2.
the b'' prefix tells you this is a sequence of 8-bit bytes, and bytes object has no unicode characters, so the u code has no special meaning. hence, b"u0432" is just the sequence of the bytes ,u,0,4,3 and 2.
本质上，您有一个 8 位字符串，其中不包含 unicode 字符，而是包含 unicode 字符的规范.
essentially you have an 8-bit string containing not a unicode character, but the specification of a unicode character.
您可以使用 unicode 转义编码器转换此规范.
you can convert this specification using the unicode escape encoder.
>>> c.decode('unicode_escape')
'в'
