统计一个目录下的子目录的size（清理program files文件夹神器）-尊龙凯时

统计一个目录下的子目录的size（清理program files文件夹神器）
#----------------------------------------------------------------
# -*- coding: utf-8 -*-
#!/usr/bin/env python
#----------------------------------------------------------------
#   author : pcfeng502
#
#   e-mail : pcfeng502@126.com
#
#   file   : foldersizelist_v02.py
#
#   introduction:
#   统计一个文件夹下的子文件夹的大小
#	方便删除文件夹中的子文件夹
#----------------------------------------------------------------
# works with python 3.3.2; windows 7 64bit
import os
from os.path import join
from os.path import getsize
exceptioncount = 0;
def getdirsize(dir):
    size = 0;
    if os.path.isdir(dir):
        for root, dirs, files in os.walk(dir):
            try:
                size  = sum(getsize(join(root, name)) for name in files)
            except filenotfounderror:
                global exceptioncount
                exceptioncount  =1
        return size;
    else:
        size = getsize(dir)
        return size
def getsubdir(dir):
    subdirlist = os.listdir(dir)
    return subdirlist
#todo
##def getpath():
if __name__ == '__main__':
    #todo read the file name input
    path = input('input the path you want to check out size\n');
    rootpath = path;
    print(rootpath);
    
    subdir = getsubdir(rootpath);
    wholedirsize = 0;
    subdirsize = [];
    print('there are', len(subdir), 'files folders in', rootpath);
    for i in range(len(subdir)):
        subdirsize.append(getdirsize(join(rootpath, subdir[i])));
        wholedirsize  = subdirsize[i];
        print('there are %.3f'%(subdirsize[i]/1024/1024), 'mbytes in', subdir[i]);
    print('there are %.3f' %(wholedirsize/1024/1024), 'mbytes in', rootpath);
    print('there are %d' %(exceptioncount), 'errors in counting');